An Encyclopaedia of Architecture, Historical, Theoretical, & PracticalLongmans, Green, and Company, 1891 - 1443 pages |
From inside the book
Results 11-15 of 80
Page 296
... becomes the radius CA , which is the least it can be . As the arc increases from 0 , the sines , tangents , and secants all increase , till the arc becomes a whole quadrant AD ; and then the sine is the greatest it can be , being equal ...
... becomes the radius CA , which is the least it can be . As the arc increases from 0 , the sines , tangents , and secants all increase , till the arc becomes a whole quadrant AD ; and then the sine is the greatest it can be , being equal ...
Page 303
... become each equal to CA , and HI becomes equal to CE ; therefore Coroll . 1 . CE ? PM2 : CE2 :: AP x PB : CA2 ; And , alternately , CA2 : CE :: AP Ć PB :: PM2 , 1 E M B P HC D Fig . 409 . Hence , if we divide the two first terms of the ...
... become each equal to CA , and HI becomes equal to CE ; therefore Coroll . 1 . CE ? PM2 : CE2 :: AP x PB : CA2 ; And , alternately , CA2 : CE :: AP Ć PB :: PM2 , 1 E M B P HC D Fig . 409 . Hence , if we divide the two first terms of the ...
Page 306
... become equal to PM , and CH ā¾ become equal to CP ; therefore , substituting in the equation 2CP for CP + PH , and 21 for ... becomes a circle , draw QT p pendicular to CQ , and joining TM , then TM will be a tangent to the ellipsis at M ...
... become equal to PM , and CH ā¾ become equal to CP ; therefore , substituting in the equation 2CP for CP + PH , and 21 for ... becomes a circle , draw QT p pendicular to CQ , and joining TM , then TM will be a tangent to the ellipsis at M ...
Page 312
... becomes CA : CE2 : :( CP + CH ) PH : ( HI + HN ) NI . So that the square of the transverse axis is to the square of ... become equal to PM , and CH equal to CP : therefore in the equation substitute 2CP for CP + CH , and 2PM for IH + HN ...
... becomes CA : CE2 : :( CP + CH ) PH : ( HI + HN ) NI . So that the square of the transverse axis is to the square of ... become equal to PM , and CH equal to CP : therefore in the equation substitute 2CP for CP + CH , and 2PM for IH + HN ...
Page 326
... becomes a sector of a circle A " B " BC " ( fig . 498. ) whose radius is equal to the side AC of the cone , and the arc equal to the circumference of the circle which is its base . 1177. Upon this may be traced the developement of the ...
... becomes a sector of a circle A " B " BC " ( fig . 498. ) whose radius is equal to the side AC of the cone , and the arc equal to the circumference of the circle which is its base . 1177. Upon this may be traced the developement of the ...
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Common terms and phrases
15th century aisles arch architect architecture axis base beam breadth bricks building built called cast iron Castle cathedral cement centre of gravity chapel choir church circle circumference colour columns construction Corinthian order cube cubic foot curve decorated describe diameter dome Doric order draw edifices ellipsis employed entablature equal erected examples extrados feet flange front girder Gothic granite half height horizontal inches joints length lime limestone marble material mortar mouldings nave obtained oolite ornaments palace parallel parallelogram perpendicular piers placed plane plates portico Portland stone Prop proportion pyramid quarries radius rectangle ribs right angles right line Roman Roman architecture Rome roof sand sandstone side similar sofite solid square stone strength style surface tangent temple thickness tiles timber tons tower transepts triangle upper vault vertical Vitruvius voussoirs walls whereof width wood