## An Encyclopaedia of Architecture, Historical, Theoretical, & Practical |

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Page 265

is perpendicular to the line AB , if the angles CDA , CDB contain an equal

number of degrees . 19. Two lines are

from one to the other are equal , thus , the lines FG , AB ( fig . 228. ) are

paIdddddddd ...

is perpendicular to the line AB , if the angles CDA , CDB contain an equal

number of degrees . 19. Two lines are

**parallel**when all perpendiculars drawnfrom one to the other are equal , thus , the lines FG , AB ( fig . 228. ) are

paIdddddddd ...

Page 268

f a line be perpendicular to one of two

other . Let AB , CD ( fig . 247. ) be two

angles » CI ) , it will also make right angles with AB . Take at pleasure GC equal

to ...

f a line be perpendicular to one of two

**parallel**lines , it is also pendicular to theother . Let AB , CD ( fig . 247. ) be two

**parallel**lines · if the line FG makes rightangles » CI ) , it will also make right angles with AB . Take at pleasure GC equal

to ...

Page 269

252 .

four angles being right angles . In the triangles GLF , FMG the sides LF , GM are

equal , because they are opposite ides of the same rectangle ; the sides LG , FM

...

252 .

**parallel**line GD Whence the quadrilateral figure GLFM is a rectangle , itsfour angles being right angles . In the triangles GLF , FMG the sides LF , GM are

equal , because they are opposite ides of the same rectangle ; the sides LG , FM

...

Page 271

Parallelograms which are between the same

, are equal . Let the two parallelograms ABCD , AFGD ( fig . 261. ) , be between

the same

Parallelograms which are between the same

**parallels**, and have the Beste base, are equal . Let the two parallelograms ABCD , AFGD ( fig . 261. ) , be between

the same

**parallels**BG , AM , and upon the same base AD ; the space enclosed ... Page 272

M Draw the right lines MC , AD , and draw AG

square or parallelogram MLAB and the triangle MCB are between the same

equal to ...

M Draw the right lines MC , AD , and draw AG

**parallel**to BD . Because thesquare or parallelogram MLAB and the triangle MCB are between the same

**parallels**LC , MB , and have the same base MB , the triangle MCB is ( Prop . 29. )equal to ...

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angle appears arch architect architecture base beam becomes bricks building built called carried cast cathedral cement centre century church circle colour columns common considered construction contains course covered curve describe diameter direction divided draw effect employed equal erected examples face feet foot force four front give given greater ground half height horizontal inches iron Italy joints length less lime marble material means mouldings nearly necessary observed obtained ornaments parallel period perpendicular placed plane portion produced Prop proportion quarries radius remains respect Roman roof says side similar solid square stone strength style supposed surface temple thickness timber tons tower triangle upper usually vault vertical walls whole wood