An Encyclopaedia of Architecture, Historical, Theoretical, & Practical |
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Page 266
From the point A , with the radius AB , describe the cir . cumference BCD , and
from the point B , with the radius BA , describe the circumference ACF ; and from
the point C , where these two circumferences cut each other , draw the two right ...
From the point A , with the radius AB , describe the cir . cumference BCD , and
from the point B , with the radius BA , describe the circumference ACF ; and from
the point C , where these two circumferences cut each other , draw the two right ...
Page 267
267 AB draw the equilateral triangle AFB , draw also the right line DF ; AC is
equal w CB . In the two larger triangles DAF , DBF the sides DA , DB are equal ,
because they are the sides of an equilateral triangle ; the sides AF , BF are equal
for ...
267 AB draw the equilateral triangle AFB , draw also the right line DF ; AC is
equal w CB . In the two larger triangles DAF , DBF the sides DA , DB are equal ,
because they are the sides of an equilateral triangle ; the sides AF , BF are equal
for ...
Page 268
... perpendiculars CA , DB , and draw the lines GA , GB . In the two triangles ACG
, BDG , because the line AB is parallel to the line CD ) , the perpendiculars CA ,
DB are necessarily equal , as appears from the definition of parallel lines ( Defin .
... perpendiculars CA , DB , and draw the lines GA , GB . In the two triangles ACG
, BDG , because the line AB is parallel to the line CD ) , the perpendiculars CA ,
DB are necessarily equal , as appears from the definition of parallel lines ( Defin .
Page 269
Through a given point to draw a line parallel te a giren line . Let G be the point
through which it is required to draw a line parallel to the given line MĚ . From any
point G ( fig . 254. ) describe , at pleasure , the are FN ; from the point F , in which
...
Through a given point to draw a line parallel te a giren line . Let G be the point
through which it is required to draw a line parallel to the given line MĚ . From any
point G ( fig . 254. ) describe , at pleasure , the are FN ; from the point F , in which
...
Page 271
and the triangle AFD he upon the same base AD , and between the same
parallels BG , AL ; the triangle AFD is half the parallelogram ABCD . Draw DG
parallel to AF . Because the parallelogram AFGD is bisected by the diagonal FD (
Prop .
and the triangle AFD he upon the same base AD , and between the same
parallels BG , AL ; the triangle AFD is half the parallelogram ABCD . Draw DG
parallel to AF . Because the parallelogram AFGD is bisected by the diagonal FD (
Prop .
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Bibliographic information
| Title | An Encyclopaedia of Architecture, Historical, Theoretical, & Practical |
| Author | Joseph Gwilt |
| Editor | Wyatt Angelicus Van Sandau Papworth |
| Edition | revised |
| Publisher | Longmans, Green, and Company, 1891 |
| Length | 1443 pages |
| Export Citation | BiBTeX EndNote RefMan |