## An Encyclopaedia of Architecture, Historical, Theoretical, & Practical |

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Page 266

From the point A , with the radius AB , describe the cir . cumference BCD , and

from the point B , with the radius BA , describe the circumference ACF ; and from

the point C , where these two circumferences cut each other ,

From the point A , with the radius AB , describe the cir . cumference BCD , and

from the point B , with the radius BA , describe the circumference ACF ; and from

the point C , where these two circumferences cut each other ,

**draw**the two right ... Page 267

267 AB

equal w CB . In the two larger triangles DAF , DBF the sides DA , DB are equal ,

because they are the sides of an equilateral triangle ; the sides AF , BF are equal

for ...

267 AB

**draw**the equilateral triangle AFB ,**draw**also the right line DF ; AC isequal w CB . In the two larger triangles DAF , DBF the sides DA , DB are equal ,

because they are the sides of an equilateral triangle ; the sides AF , BF are equal

for ...

Page 268

... perpendiculars CA , DB , and

, BDG , because the line AB is parallel to the line CD ) , the perpendiculars CA ,

DB are necessarily equal , as appears from the definition of parallel lines ( Defin .

... perpendiculars CA , DB , and

**draw**the lines GA , GB . In the two triangles ACG, BDG , because the line AB is parallel to the line CD ) , the perpendiculars CA ,

DB are necessarily equal , as appears from the definition of parallel lines ( Defin .

Page 269

Through a given point to

through which it is required to

point G ( fig . 254. ) describe , at pleasure , the are FN ; from the point F , in which

...

Through a given point to

**draw**a line parallel te a giren line . Let G be the pointthrough which it is required to

**draw**a line parallel to the given line MĚ . From anypoint G ( fig . 254. ) describe , at pleasure , the are FN ; from the point F , in which

...

Page 271

and the triangle AFD he upon the same base AD , and between the same

parallels BG , AL ; the triangle AFD is half the parallelogram ABCD .

parallel to AF . Because the parallelogram AFGD is bisected by the diagonal FD (

Prop .

and the triangle AFD he upon the same base AD , and between the same

parallels BG , AL ; the triangle AFD is half the parallelogram ABCD .

**Draw**DGparallel to AF . Because the parallelogram AFGD is bisected by the diagonal FD (

Prop .

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