## An Encyclopaedia of Architecture, Historical, Theoretical, and Practical |

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Page 289

The

equal to FM . ... as the squares of their

the ...

The

**radius**AL is equal to the**radius**AD : but AD is equal to FM ; therefore AL isequal to FM . ... as the squares of their

**radii**; therefore , since the square of the**radius**FM is equal to the squares of the**radii**FL and FG , the circular section ofthe ...

Page 567

Subtract the

be the

The difference ab between a F and I F will form one side of the quadrilateral ubcd

...

Subtract the

**radius**af so found from the height H BD and the remainder FD willbe the

**radius**of the second quarter of the revolution , and is to be set from F to b .The difference ab between a F and I F will form one side of the quadrilateral ubcd

...

Page 573

Then EC will be the smaller

. For arches whose height is greater than their half width ( fig . 629b . ) , draw CF

and BE perpendicular to AC , then EC will be the smaller

Then EC will be the smaller

**radius**, and EC added to AD will be the longer**radius**. For arches whose height is greater than their half width ( fig . 629b . ) , draw CF

and BE perpendicular to AC , then EC will be the smaller

**radius**; and EC added ...### What people are saying - Write a review

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